Let u = sin θ. Then du = cos θ dθ and. / 8 cos θ cos5(sin θ) dθ = / 8 cos5 u du = / 8(cos2 u)2 cos u du. = / 8(1 - sin2 u)2 cosu du. = / 8(1 - 2 sin2 u + sin4 u) cos u 

−3 r2 a2 sin θ cos ϕr +. (a r. − r2 a2. )( cos θ cos ϕˆθ − sin ϕˆϕ. )] (2) 1 r2 sin θ. [g cos ϕ (cos2 θ − sin2 θ)] − g r2 cos ϕ sin θ. = 2 f r. + f +.

This can be viewed as a version of the Pythagorean theorem, and follows from the equation x2 + y2 = 1 for the unit circle. Free trigonometric equation calculator - solve trigonometric equations step-by-step sin ^2 (x) + cos ^2 (x) = 1 . tan ^2 (x) + 1 = sec ^2 (x) . cot ^2 (x) + 1 = csc ^2 (x) . sin(x y) = sin x cos y cos x sin y Solve for ?

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sin(x y) = sin x cos y cos x sin y Solve for ? cos (theta)=- (square root of 2)/2 cos (θ) = − √2 2 cos (θ) = - 2 2 Take the inverse cosine of both sides of the equation to extract θ θ from inside the cosine. θ = arccos(− √2 2) θ = arccos (- 2 2) This is a well used trig. relation along with sin(π 2 −θ) that is : cos(π 2 − θ) = sinθ and sin(π 2 −θ) = cosθ Basically sin (angle) = cos (complement) and cos (angle) = sin (complement) Notice how a "co- (something)" trig ratio is always the reciprocal of some "non-co" ratio. You can use this fact to help you keep straight that cosecant goes with sine and secant goes with cosine. The following (particularly the first of the three below) are called "Pythagorean" identities. sin 2 (t) + cos 2 (t) = 1 Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

Section Solution from a resource entitled Can we write $\sin\theta$ and $\cos\theta$ in terms of $\tan(\theta/2)$?.

hjälp: d du log(sin2 u cos u) = 3 cos2 u−1 sin u cos u .) (10 poäng). 5.

Now using quadratic formula cosθ = −(− 1) ± √(− 1)2 −4 ⋅ 2 ⋅ (−1) 2 ⋅ 2 or cosθ = 1 ± √1 +8 4 = 1 ± 3 4 Hence cosθ = 1 = cos0 or cosθ = − 1 2 = cos(2π 3)

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cosinus lyder cos 2θ = 2 cos2 θ − 1. Om vi tar θ = π.

2 minutes ago Using the method of completing the square to solve the quadratic equation  E[X] = E[Y] = 0 $. $ E[X] = \sigma_X^2 $.
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$y = \sqrt{r^2 + a^2} sin \theta sin \phi$ $z = r cos \theta$ $ds^2 = -dt^2 + \Sigma (\frac{1}{\Delta} dr^2 + d\theta^2) + (r^2 + a^2) sin^2 \theta d\phi^2 + \frac{2 M 

A. ∫ dx sin(x + θ). = 1.

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2\sin ^2 (x)+3=7\sin (x),\:x\in [0,\:2\pi ] 3\tan ^3 (A)-\tan (A)=0,\:A\in \: [0,\:360] 2\cos ^2 (x)-\sqrt {3}\cos (x)=0,\:0^ {\circ \:}\lt x\lt 360^ {\circ \:} Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history cotangent eller kotangent. cot (ibland ctg eller ctn) närliggande/motstående.